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5x^2=200-15x
We move all terms to the left:
5x^2-(200-15x)=0
We add all the numbers together, and all the variables
5x^2-(-15x+200)=0
We get rid of parentheses
5x^2+15x-200=0
a = 5; b = 15; c = -200;
Δ = b2-4ac
Δ = 152-4·5·(-200)
Δ = 4225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4225}=65$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-65}{2*5}=\frac{-80}{10} =-8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+65}{2*5}=\frac{50}{10} =5 $
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